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defon
3 years ago
13

What conclusions can you draw about the two track teams from the data shown?

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0
Where is the data that is shown?
kumpel [21]3 years ago
3 0
Which data shown exactly?
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PLEASE HELP !! I'LL GIVE YOU BRAINLIEST !!
GuDViN [60]

Answer:

B

Step-by-step explanation:

tan45° = 10/x

=> 1 = 10/x

=> x = 10

=> y^2 = 10^2 + 10^2 = 200

=> y = 100*sqrt(2)

=> b

5 0
2 years ago
The sum of three consecutive odd integers is 17 less than four times the smallest integer
Lilit [14]

x = smallest \: int \\ x + (x + 2) + (x + 4) = 4x - 17 \\ 3x + 6 = 4x - 17 \\ 23 = x \\ numbers = 23 \: 25 \: 27
4 0
3 years ago
Mid Linear Equation // ALGEBRA I HELP PLSS
Rzqust [24]

Answer:

1. y = -125000x + 700000

2. Negative

3. Positive

Step-by-step explanation:

1. The no. Of gallons before irrigation

= 700000

After irrigation = 200000

This means that there was a reduction of 500000 gallons in 4 hours which indicates that 125000 gallons were used (on an average) in 1 hour

So the equation is

y = 700000 - 125000x

Hope this helps

Can u plz mark me as brainliest?

My rank needs to increase so plz

8 0
3 years ago
What expression is equivalent to -19x+8y-2+7-40y+43​
Bogdan [553]

Answer:

- 19 \times  - 32y + 48

5 0
3 years ago
Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
mars1129 [50]

Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

Answer:

11/288

Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.

Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

P[E(B1)]= 0

P[E/B3)] = (2 2) / (4 2)

= 1/6

If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:

P(E/B2) = (1/4) *(1/4)

= 1/16

Therefore probability that 2 balls extracted are red, we have:

P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 0 * \frac{1}{3} + \frac{1}{6}*\frac{1}{3} + \frac{1}{16}*\frac{1}{3}

= 11/288

3 0
3 years ago
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