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defon
3 years ago
13

What conclusions can you draw about the two track teams from the data shown?

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0
Where is the data that is shown?
kumpel [21]3 years ago
3 0
Which data shown exactly?
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Explain how you can use a number line to find the sum of 4+(-8)
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-4

Step-by-step explanation:

you add to the left of a positive to negative

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What is the m∠ABC?<br><br> 1)m∠ABC = 60°<br> 2)m∠ABC = 67°<br> 3)m∠ABC = 120°<br> 4)m∠ABC = 127°
docker41 [41]

we are given

m∠BCD =67

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4 years ago
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Consider the exponential function g(x)=100(2)^x which of the following situations could be modeled by the function
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3 years ago
40 points and brainliest to the best correct answer, questions in photo.
vodomira [7]

Answer:

2. w = -3

4. c = -2

6. r = 7

8. n = 4

Step-by-step explanation:

It's hard to read the photo, but I'll try.

2.

2^{w + 4} \times 2^{4w + 6} = 2^{2w + 1}

On the left side, you have a product of 2 powers with the same base.

Give the same base and add the exponents, as in the rule

a^m \times a^n = a^{m + n}

You get on the left side 2 to the sum of the exponents.

2^{w + 4 + 4w + 6} = 2^{2w + 1}

Simplify the long exponent on the left side.

2^{5w + 10} = 2^{2w + 1}

Now we have another rule we can use. If two powers are equal, and their bases are equal, then the exponents must be equal.

Here, 2 to the power 5w + 10 equals 2 to the power 2w + 1. Since both bases are 2 and are equal, then the exponents must be equal.

5w + 10 = 2w + 1

Subtract 2w from both sides. Subtract 10 from both sides.

3w = -9

Divide both sides by 3.

w = -3

4.

\dfrac{1}{5} = 5^{2c + 3}

We need to write the left side as a power of 5. Then we equate the exponents like we did in problem 2.

Recall the rule:

a^{-n} = \dfrac{1}{n}

Apply this rule to the left side in reverse.

5^{-1} = 5^{2c + 3}

Now we have two powers that are equal, both having the same base, 5, so the exponents must be equal.

2c + 3 = -1

2c = -4

c = -2

6.

216 = 6^{2r - 11}

This is the same idea as problem 4. Write the left side as a power of 6.

6^3 = 6^{2r - 11}

2r - 11 = 3

2r = 14

r = 7

r = 7

8.

4^{n} \times 4^{2n - 9} = 64

This problem is similar to problem 2.

4^{n + 2n - 9} = 4^3

4^{3n - 9} = 4^3

3n - 9 = 3

3n = 12

n = 4

4 0
2 years ago
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