Answer:
1/2 ( the two answers given are not FRACTIONS)
Explanation:
Moles of CH3OH = 128 gm / 32 gm / mole = 4 moles
Moles of water 72 gm / 18 gm /mole = 4
Mole fraction of CH3OH = 4 / ( 4+4) = 4/8 = 1/2
When discussing discordant and harmonious sound waves, the statement tat is false is : if the original waves combine to form irregular displacement of air, the sound will be discordant. The fact is, irregular displacement of air does not guarantee sound discordance
hope this helps
A chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Classically, chemical reactions encompass changes that only involve the positions of electrons in the forming and breaking of chemical bonds between atoms, with no change to the nuclei (no change to the elements present), and can often be described by a chemical equation.
Butyne is the alkyne with four carbon atoms, and, as the question states, it has one carbon-carbon triple bond. The general formula of an alkyne is CnH2n-2, that means that when there are 2 carbons the formula is C2H2, when there are 3 carbons the formula is C3H4, and when there are 4 carbons the formula is C4H6. So, <span>butyne is C4H6 or " CH3-C (triple bond) C - CH3" (note that I wrote the phrase triple bond between the two Cs in the middle of the formula because there is no way to draw the three hyphens stacked one over other").</span>
Answer:
1. Balanced
2. Unbalanced
3. Unbalanced
Explanation:
<em>Identify which of the following oxidation-reduction reactions are balanced and which are unbalanced in both mass and charge.
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<em>
</em>
<em>1. Ag⁺(aq) + Li(s) → Ag(s) + Li⁺(aq)
</em>
This reaction is balanced in both mass and charge.
<em>2. Fe(s) + Na⁺(aq) → Fe²⁺(aq) + Na(s)
</em>
This reaction is balanced in mass but unbalanced in charge since the charge to the left is +1 and the charge to the right is 2+.
<em>3. K(s) + H₂O(l) → KOH(aq) + H₂(g)</em>
This reaction is balanced in charge but unbalanced in mass since there are 2 atoms of H to the left and 3 atoms of H to the right.
