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earnstyle [38]
2 years ago
5

Isotopes are different types of atoms of the same element, but with a different number of __________ ?

Chemistry
2 answers:
rodikova [14]2 years ago
6 0
Same things but with different numbers of neutrons in nuclei
bija089 [108]2 years ago
4 0

Answer:

A different atomic mass, which means that there is a varying number of nuetrons in the nucleus between isotopes.

Explanation:

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for the given reaction, what volume of o2 would be required to react with 4.8 l of co , measured at the same temperature and pre
SVEN [57.7K]

We can see that 2 moles of The no react with 1 mole of O2 using this equation. 4.8 L NO x 1 L O2 / 2 L NO = 2.4 L of O2 are needed at constant pressure and temperature.

What is an example of pressure?

One can see a simple illustration of pressure by using a knife against a few fruit. If you press the flat side of the knife against the fruit, the top won't be cut. The force is spread more than a wide area (low pressure).

What are different types of pressure?

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7 0
1 year ago
“True or False”
Sliva [168]
True, I’m sorry if I’m wrong
3 0
2 years ago
Together oxygen and nitrogen comprise what percentage of the atmosphere
Charra [1.4K]
Oxygen is 21% and nitrogen is 78% so combined is 99%
5 0
3 years ago
In which of the following reactions is chlorine (Cl) oxidized? Br2 + 2Cl− → Cl2 + 2Br− Cl2 + 2e− → 2Cl− 2ClO3− + 12H+ → Cl2 + 6H
Tomtit [17]

2CIO3 is the answer to your question

7 0
2 years ago
Read 2 more answers
Ammonia and oxygen react to form nitrogen and water.
Nata [24]

Answer:

A. 19.2 g of O2.

B. 3.79 g of N2.

C. 54 g of H2O.

Explanation:

The balanced equation for the reaction is given below:

4NH3(g) + 3O2(g) → 2N2+ 6H2O(g)

Next, we shall determine the masses of NH3 and O2 that reacted and the masses of N2 and H2O produced from the balanced equation.

This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17 g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96 g

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 from the balanced equation = 2 x 28 = 56 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 6 x 18 = 108 g

Summary:

From the balanced equation above,

68 g of NH3 reacted with 96 g of O2 to produce 56 g of N2 and 108 g of H2O.

A. Determination of the mass of O2 needed to react with 13.6 g of NH3.

This is illustrated below:

From the balanced equation above,

68 g of NH3 reacted with 96 g of O2.

Therefore, 13.6 g of NH3 will react with = (13.6 x 96)/68 = 19.2 g of O2.

Therefore, 19.2 g of O2 are needed for the reaction.

B. Determination of the mass of N2 produced when 6.50 g of O2 react.

This is illustrated below:

From the balanced equation above,

96 g of O2 reacted to produce 56 g of N2.

Therefore, 6.5 g of O2 will react to produce = (6.5 x 56)/96 = 3.79 g of N2.

Therefore, 3.79 g of N2 were produced from the reaction.

C. Determination of the mass of H2O formed from the reaction of 34 g of NH3.

This is illustrated below:

From the balanced equation above,

68 g of NH3 reacted to 108 g of H2O.

Therefore, 34 g of NH3 will react to produce = (34 x 108)/68 = 54 g of H2O.

Therefore, 54 g of H2O were obtained from the reaction.

4 0
2 years ago
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