A backpack is normally $64.99 but is discounted ti $45.49. What percent of the original does Maria pay?

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

d.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

e.

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

f.

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

7 0

3 years ago

Why might the mean of a probability distribution for a discrete random variable be less than (or greater than) the average of po

user100 [1]

The Normal probability distribution function is left-skewed, right-skewed, or symmetric depending on the values of the variance and the standard deviation might the mean of a probability distribution for a discrete random variable be less than (or greater than) the average of possible values.

A probability distribution is a mathematical function that describes the probabilities of different possible values of a variable. Probability distributions are often represented using graphs or probability tables.

Probability distributions are called discrete probability distributions, and the set of outcomes is inherently discrete. For example, if you roll a die, all possible outcomes are discrete and you get a large number of outcomes. Also called probability mass function.

Learn more about probability distribution at

brainly.com/question/9385303

#SPJ4

4 0

1 year ago

Complete the double number to line show percentages of $50

malfutka [58]

Can you send us a picture of the question please

8 0

3 years ago

Evaluate the expression 2b^3+5 (BTW I did the first part it's 3 but I need the second part)

andrey2020 [161]

To find the exact answer based on the last step, " $2(3)^3+5$ ", you must use PEMDAS (attached image below)

$2(3)^3+5=2*27+5=54+5=59$

Thus the answer is <u>59</u>.

Hope that helps!

4 0

2 years ago

The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is given below, where k is th

andrew11 [14]

The average rate of blood flow is given by

$\displaystyle\frac1{R-0}\int_0^Rv(r)\,\mathrm dr=\frac kR\int_0^R(R^2-r^2)\,\mathrm dr$
$=\dfrac kR\left(R^2r-\dfrac13r^3\right)\bigg|_{r=0}^{r=R}$
$=\dfrac kR\left(R^3-\dfrac13R^3\right)$
$=\dfrac{2kR^2}3$

3 0

2 years ago