Question

two integers, a and b, have different signs. the absolute value of inter a is divisible by the absolute value of integer b. Find two integers that fit this description. Then decide if the product of the integers is greater than or less than the quotient of the integers.

Answer 1

Two numbers that meet the condition are a = -10 and b = 2, and the quotient between these is larger than the product.

How to find two integers that fit the description?

We have two numbers a and b with different sign.

Let's say that a is negative and b positive.

We know that the absolute value of a is divisible by the absolute value of b.

|a|/|b|

Then we have that |a| ≥ |b|

An example of two numbers that meet these conditions are:

a = -10

b = 2

Where:

|-10|/|2|  = 10/2 = 5

Now, the product between the integers will give a large negative number, in this case:

-10*2 = 20

and the quotient will give a smaller, in absolute value, negative number:

-10/2 = -5

Then we can see that the quotient is larger (as both are negative numbers, and the quotient is closer to zero).

If you want to learn more about absolute values:

brainly.com/question/24368848

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