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3 years ago

What is the value of X.

Mathematics

2 answers:

elena55 [62]3 years ago

5 0

Answer:

x=5.25 or x=5 1/4

Step-by-step explanation:

These two angles are the same because they are vertical angles. We can write an equation to express this.

x+16=4x-5

Then solve.

x+16=4x-5

-x -x

16=4x-5

+5 +5

4x=21

x=5.25 or 5 1/4

Alex3 years ago

5 0

Answer: x=7

Explanation: These are vertical angles, so they are congruent

x+16=4x-5

-x -x

16=3x-5

+5 +5

21=3x

21/3 3x/3

x=7

7+16=23
4*7=28-5=23

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Given line segment AB, the coordinates of A are (3,-5) and the coordinates midpoint are (5,-1), what are the coordinates for B?

dsp73

Answer:

Step-by-step explanation:

Point P(5, -1) being the midpoint of AB means that $x_P-x_A=x_B-x_P$

$5-3=x_B-5\\\\2+5=x_B\\\\x_B=7$

and $y_P-y_A=y_B-y_P$

$-1-(-5)=y_B-(-1)\\\\-1+5=y_B+1\\\\y_B=3$

6 0

3 years ago

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$