Answer:
I'm not smart but I think there's no solution
Answer:
313°
Step-by-step explanation:
The reference angle (α) can be found using the tangent relation:
Tan = Opposite/Adjacent
__
In this problem, that means ...
tan(α) = 78/83
α = arctan(78/83) ≈ 43° . . . . . . angle from -x axis
The bearing angle will be this value added to 270°, since bearing angles are measured clockwise from north.
bearing = 270° +43° = 313°
F(x)=-x2+5n
g(x)=-2n+15
A(x)=|g(x)-f(x)|=|x2-7n+15|
x2-7n+15>0 for every x (1)
A(x)=x2-7n+15
(1):
x2-7n+15=(x-3.5)^2-12.25+15=(x-3.5)^2+2.75 > 0
because for every x: (x-3.5)^2>=0
answer: A(x)=x2-7n+15
Answer:
Step-by-step explanation:
we know that
In the diagram
Equate