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blagie [28]
3 years ago
8

Find the coordinate of the points of intersection of the graphs without building them: 20x - 15y = 100 and 3x - 5 =6y

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0

9514 1404 393

Answer:

  (x, y) = (7, 2 2/3)

Step-by-step explanation:

We can multiply the first equation by 2/5 to get ...

  8x -6y = 40

The second equation gives an expression for 6y that we can substitute.

  8x -(3x -5) = 40

  5x +5 = 40 . . . . . eliminate parentheses

  x +1 = 8 . . . . . . . .divide by 5

  x = 7 . . . . . . . . . .subtract 1

Using the second equation, we find ...

  3(7) -5 = 6y

  y = 16/6 = 2 2/3

The coordinates of the point of intersection are (x, y) = (7, 2 2/3).

Mekhanik [1.2K]3 years ago
5 0

Answer:

(-4.666667, -3.16667)

Step-by-step explanation:

(-4 2/3, -3 1/6)

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Answer:

<h2>10:00 Pm</h2>

Step-by-step explanation:

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Now let's see what the correct time should be:

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at 2:09 it is really 3:00

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However, it says the watch stopped 6 hours ago meaning that the time should be 10:00 as 4 + 6 = 10.

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3 years ago
How do you use the order of operations to simplify expression with exponent
insens350 [35]
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Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?
oee [108]
The answer is \frac{x^{4/3}y^{3}}{3}.

The fraction is: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5}  }
Let's rewrite it: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }

Since \frac{x^{a} }{x^{b}} =x^{a-b},
then:
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______
\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}
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