Answer:
A 180-pound kangaroo's recommended height is 6 feet.
Step-by-step explanation:
Since 120-pound kangaroo is 5 feet tall and for every inch over this height we add 5 pounds to the total weight, we can make this formula. . Using this we can figure out the weight difference between a 120-pound kangaroo and a 180-pound kangaroo. After solving for x we get .
Now that we know the 180-pound kangaroo weighs 60 more pounds than a 120-pound kangaroo we can divide that weight difference by 5 to figure out the height difference.
After getting the height difference from the weight difference we can conclude that a 180-pound kangaroo's recommended height is 5 feet and 12 inches. Since 12 inches = 1 foot we can easily convert 5' 12" to 6'. This means that a 180-pound kangaroo is 6 feet tall.
3x < 18
3x/3 < 18/3
x < 6
Hope this helps !
Photon
Answer:
ED = 8 units
Step-by-step explanation:
ΔAEB and ΔDEC are similar triangles, hence the ratios of corresponding sides are equal, that is
= , that is
= ( cross- multiply )
6(2x + 4) = 9(x + 4) ← distribute parenthesis on both sides
12x + 24 = 9x + 36 ( subtract 9x from both sides )
3x + 24 = 36 ( subtract 24 from both sides )
3x = 12 ( divide both sides by 3 )
x = 4
Hence ED = x + 4 = 4 + 4 = 8 units
Answer: see the graphic
Step-by-step explanation:
A. Type I error helps us to conclude that the flight is not profitable, when in fact it is profitable.
B. a = 0.05
C. Type II error does not show that the flight is profitable