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Delicious77 [7]

2 years ago

9

David bought three candy bars for $2.45. Assuming that each candy bar is the same price, what is the unit rate for the cost of t

he candy bars? Be sure to round your answer to the nearest hundredth.

1 answer:

xxMikexx [17]2 years ago

6 0

Answer:

$4.55

Please give me the brainliest!

Hope this helps!

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Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =

Semmy [17]

Answer:

The rate of interest for compounded annually is 6.96 % .

Step-by-step explanation:

Given as :

The principal amount = Rs 4600

The time period = 5 years

The amount after 5 years = Rs 6440

Let The rate of interest = R %

<u>From compounded method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm Time}$

or, Rs 6440 = Rs 4600 × $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $\frac{6440}{4600}$ = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

or, 1.4 = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $(1.4)^{\frac{1}{5}}$ = 1 + $\dfrac{R}{100}$

or, 1.0696 = 1 + $\dfrac{R}{100}$

or, $\dfrac{R}{100}$ = 1.0696 - 1

Or, $\dfrac{R}{100}$ = 0.0696

∴ R = 0.0696 × 100

I.e R = 6.96

Hence The rate of interest for compounded annually is 6.96 % . Answer

5 0

3 years ago

2. An expression is shown below.

velikii [3]

The answer is B12 hope this helped

5 0

3 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is

NikAS [45]

Answer:

132 cm. 3. 3. a rectangular pyramid with a height of 5.2 meters and a base 8 ... 7. an oblique cone with a height of 10.5 millimeters and a radius of 1.6 ... base is about 15,400 square feet, find the volume of air that the ... ANSWER: 32.2 ft. 3. Find the volume of each solid. Round to the nearest tenth. eSolutions ...

Step-by-step explanation:

8 0

3 years ago

No referencial está representado o círculo trigonométrico e um ponto A, resultante da intersecção da circunferência como lado ex

Anna35 [415]

Answer:

??

Step-by-step explanation:

8 0

3 years ago

Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a

stepan [7]

4s+7a=861
s+a=168

This can be solved using either elimination or substitution. I am going to use substitution.

Solve s+a=168 for s
s=168-a

Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861

Solve for a
672+3a=861
3a=189
a=63

Substitute 63 for a in s=168-a
s=168-63=105

So, s=105 student tickets and a=63 adult tickets

3 0

3 years ago