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olga55 [171]
2 years ago
10

PLZ HELP 30 POINTS!

Mathematics
2 answers:
REY [17]2 years ago
8 0

Answer:

B

Step-by-step explanation:

Nutka1998 [239]2 years ago
3 0

Answer:

i think the answer is b

Step-by-step explanation:

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Which is greatest 3/5, 0.70, or 65%? Tell how you know.
Leni [432]
3/5 = .60, 65% = .65, 0.70 is the greatest
8 0
3 years ago
A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig
Vaselesa [24]

Answer:

a) Depth changing rate of change is 0.24m/min, When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of 0.17m/min, When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them \frac{3.5}{10} =\frac{a}{h}, then a=0.35h.

a) As we have that volume is V=\frac{1}{2} 2ahL=ahL, then V=(0.35h^{2})L, so we can derivate it \frac{dV}{dt}=2(0.35h)L\frac{dh}{dt} due to the chain rule, then we clean this expression for \frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt} and compute with the knowns \frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min, is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is 2a=0.7h, we can derivate it and obtain \frac{da}{dt}=0.7\frac{dh}{dt}  =0.7*0.24m/min=0.17m/min The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0
3 years ago
 How much fencing is required to enclose a circular garden whose radius is 22 ​m? Use 3.14 for pie
galina1969 [7]

Answer:

138.16 m

Step-by-step explanation:

Circumference=2πr

r=22

C=2·3.14·22

C=138.16


3 0
3 years ago
Hao bought a 16-pound bag of dog food. If his dog eats pound of food every day, for how many days will the bag of dog food last?
densk [106]

Answer:

uh 1 pound per day 16 pounds so 16 days, i guess

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Solve the equation by using the quadratic formula.<br> 3 x squared minus 1 = 7 x
Paladinen [302]

Answer:

b.  \frac{7+\sqrt{61} }{6} ,\frac{7-\sqrt{61} }{6}

Step-by-step explanation:

3x^{2} -1=7x

Quadratic equations are suppose to be written as: ax^2+bx+c=0

so the new quadratic equation for this problem will be: 3x^{2} -1-7x=0

Now rearrange the terms: 3x^{2} -7x-1=0

Then use the Quadratic Formula to Solve for the Quadratic Equation

Quadratic Formula = x=\frac{-b±}{} \frac{\sqrt{b^2-4ac} }{2a}

Note: Ignore the A in the quadratic formula

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3x^{2} -7x-1=0

a = 3

b = -7

c = -1

x=-(-7)±\frac{\sqrt{(-7)^2-4(3)(-1)} }{2(3)}

Evaluate The Exponent

x=\frac{7±\sqrt{(49)-4(3)(-1)} }{2(3)}

Multiply The Numbers

x=\frac{7±\sqrt{49+12} }{2(3)}

Add The Numbers

x=\frac{7±\sqrt{61} }{2(3)}

Multiply The Numbers

x=\frac{7±\sqrt{61} }{6}

4 0
3 years ago
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