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3 years ago

Find the value of x.

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Answer:

1. 2=x+41

‐x=41‐2

x=‐39

2. 2=4+7×

‐7×=4‐2

7×=2

3. 2=10×+8

‐10×=8‐2

‐5×=3

5×=‐3

4.2=×+141

‐x+2=141

‐x=139

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musickatia [10]

(5,4)

x=5

y=4

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mark brainliest :)

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3 years ago

Anybody know the answer I need help. Please

Evgen [1.6K]

Answer:

$\dfrac{p^2+9p+2}{p^2-49}$

Step-by-step explanation:

Problems like this require that you recognize that the denominator of the right term is a factor of the denominator of the left term. That is, you're supposed to know how to recognize and factor the difference of two squares.

$\dfrac{5-p}{49-p^2}+\dfrac{p+1}{p-7}=\dfrac{p-5}{p^2-49}+\dfrac{p+1}{p-7}\\\\=\dfrac{p-5}{(p-7)(p+7)}+\dfrac{p+1}{p-7}\cdot\dfrac{p+7}{p+7}\\\\=\dfrac{(p-5)+(p+1)(p+7)}{(p-7)(p+7)}=\dfrac{p-5+p^2+8p+7}{p^2-49}=\dfrac{p^2+9p+2}{p^2-49}$

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3 years ago

X÷-1.2= -0.3 i need help with this asap pls and thank you

Aleks [24]

0.3×1.2

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−0.3,1.2→Negative

−0.36

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A certain high school has 1,488 students. If you subtract the number of girls from boys you get 78. Let x be the number of boys

Dahasolnce [82]

Answer:

boys = 705

girls = 783

Step-by-step explanation:

We are to find the number of boys and girls in the school

the answer can be determined using simultaneous equation

x = boys

y = girls

y - x = 78 equation 1

y + x = 1488 equation 2

subtract equation 1 from 2

2x = 1410

x = 1410/2 = 705

Substitute for x in equation 1

y - 705 = 78

y = 705 + 78 = 783

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3 years ago