All categories

2 years ago

If [2+3] [1+x]=25 what is x?

Mathematics

2 answers:

Andreyy892 years ago

7 0

Answer:

Step-by-step explanation:

2+3=5

5*(1+4)

1+4=5

5*5=25

user100 [1]2 years ago

5 0

$\boxed{\underline{\bf \: ANSWER}}$

$(2 + 3)(1 + x) = 25 \\ 5(1 + x) = 25 \\ 1 + x = 25 \div 5 \\ 1 + x = 5 \\ x = 5 - 1 \\ \boxed{x = 4}$

Note :-

Image is attached.

Hope it helps!

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

You might be interested in

Consider the following function. f(x) = |x − 9| Find the derivative from the left at x = 9. If it does not exist, enter NONE. -1

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

$f(x)=\mid x-9\mid$

$f(x)=-(x-9)$ when x<9

$f(x)=x-9$ when $x\geq 9$

LHD

$\lim_{x\rightarrow 9-}f'(x)$

= $-\lim_{x\rightarrow 9-}(x-9)=-1$

RHD

$\lim_{x\rightarrow 9+}f'(x)$

$=\lim_{x\rightarrow 9+}(x-9)=1$

$LHD\neq RHD$

Hence, the function is not differentiable at x=9

8 0

3 years ago

How do I factor x^4-5x^2+6?

Vilka [71]

Answer:

$=(x^2-3)(x^2-2)$

Step-by-step explanation:

So we have the expression:

$x^4-5x^2+6$

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

$=u^2-5u+6$

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

$=u^2-2u-3u+6$

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

$=u(u-2)-3(u-2)$

Grouping:

$=(u-3)(u-2)$

Now, substitute back the x² for u:

$=(x^2-3)(x^2-2)$

And this is the simplest form.

And we're done!

3 0

3 years ago

What is the nth term rule of the quadratic sequence below? 8,14,22,32 ,44, 58, 74...

DanielleElmas [232]

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

8 0

3 years ago

Quick, anyone know this geometry question?

scoray [572]

RS is 68 and T is 92 if you want an explanation then i gotten but u said quick so maybe it is timed idk

4 0

3 years ago

Read 2 more answers

To solve a problem, a student had to find a certain angle θ. The student got to the

stira [4]

Answer:

see explanation

Step-by-step explanation:

sinΘ is only valid for values in the interval

- 1 ≤ Θ ≤ 1

sinΘ = $\frac{5}{2}$ is outwith this interval and is not valid

3 0

3 years ago