Maurício foi apresentar a solução dessa equação no quadro 7 x + 4 = 19 7x = 19 - 47 X = 15x = 15 - 7 e x - x = 8 ele cometeu um
1 answer:
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Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In a parallelogram opposites sides are parallel and congruent
so
In this problem
---> by opposite sides
substitute the given values
solve for x
Find the length of SV
substitute the value of x
ANSWER
B) A rectangle with a length of 15 cm and a width of 9 cm.
EXPLANATION
The given rectangle, A, has length, 10cm and its width is 6cm.
The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.
For option A, the triangle has length 9cm and width 6cm.
The ratio of the corresponding sides are:
Since the ratios are not equal, the two triangles are not similar.
For the triangle in option B, the length is 15cm and the width is 9cm.
The ratio of the corresponding sides are:
Since the sides of the triangle are in the same proportion, the two triangles are similar.
For option C, the proportions are not the same.
The proportions are not the same for the triangle in option D.
B) A rectangle with a length of 15 cm and a width of 9 cm.
EXPLANATION
The given rectangle, A, has length, 10cm and its width is 6cm.
The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.
For option A, the triangle has length 9cm and width 6cm.
The ratio of the corresponding sides are:
Since the ratios are not equal, the two triangles are not similar.
For the triangle in option B, the length is 15cm and the width is 9cm.
The ratio of the corresponding sides are:
Since the sides of the triangle are in the same proportion, the two triangles are similar.
For option C, the proportions are not the same.
The proportions are not the same for the triangle in option D.
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I =
Area of ΔADC =
=
=
=
=
= 30 cm²
Area of equilateral triangle II =
Area of equilateral triangle II =
=
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH =
Since, GH = GJ + JK + KH
17 =
12 =
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² +
-81 = -x² +
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV =
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
