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Tasya [4]
3 years ago
7

Sam’s Swimming Pool Cleaning has an annual gross profit of $88,400. Sam charges $25 per week for each of his customers for 52 we

eks. His annual operating expenses, including labor and supplies, are $48,000. How many customers does Sam’s Swimming Pool Cleaning have?
a.
17
b.
35
c.
68
d.
105


The answer is C
Mathematics
2 answers:
sladkih [1.3K]3 years ago
5 0

Answer:  Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Annual gross profit of Sam's Swimming pool cleaning = $88400

So, Gross profit of Sam will be

\$88400

Now, according to question, Sam charges $25 per week for each of his customers for 52 weeks .

So, Total amount he charges for each of his customers will be

25\times 52=$1300

So, Number of customers Sam's Swimming Pool Cleaning have is given by

\frac{88400}{1300}\\\\=68

Hence, Option 'C' is correct.

m_a_m_a [10]3 years ago
3 0
To get how many customers Sam has, write an equation that will relate to the gross profit. Let n be the customers. Since for 52 weeks, Sam charges $25 per week per person, multiply n by the number of weeks and the charge. The equation is written as $88,400 = 52 weeks x $25 per week x n persons. Divide $88,400 by the product of 52 weeks and the $25 charge. The answer will be 68. The annual operating expense $48,000 is just there to make confusion. 
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\huge\text{Hey there!}


\huge\textsf{Breaking the meaning down in simpler terms}
\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}


\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}

\huge\textsf{Formulas for each term}

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\huge\textbf{SOLVING FOR THE QUESTION}

\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of  \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}

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\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
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