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Fudgin [204]
3 years ago
5

I need help to find m

Mathematics
2 answers:
harina [27]3 years ago
7 0
It’s is 75 because I did it right now
Neko [114]3 years ago
4 0

Answer:

∠MNO = 75°

Step-by-step explanation:

∠mno = 1/2 ( arc MLP - arc MOP )

arc MLP = 241 and arc MOP = 91

so ∠MNO = 1/2 ( 241 - 91 )

241 - 91 = 150

150/2 = 75

Hence, ∠MNO = 75°

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96=-8k solve <br> Show work
larisa86 [58]

Answer:

k = -12

Step-by-step explanation:

<u>Step 1:  Divide both sides by -8</u>

<u />96 / -8 = -8k / -8

-12 = k

Answer: k = -12

3 0
3 years ago
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Vanessa has scored 45, 32, and 37 on her three math quizzes. She will take one more quiz and she wants a quiz average of at leas
zhenek [66]

45 + 32 + 37 = 114

114÷3 = 38

4 total quizzes,


 for a 40 average on 4 quizzes she needs 40*4 = 160 total points




for 3 quizzes she has 45 +32 +37 = 114 points


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3 years ago
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Lisa [10]

Answer:

564.44

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8 0
2 years ago
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How do you do long divisions for 2 divided by 3339
JulijaS [17]

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Step-by-step explanation:

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3 years ago
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An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
3 years ago
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