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Annette [7]
2 years ago
5

What can you say about the end behavior of the function f(x)=log2(4x+8)+16

Mathematics
2 answers:
adoni [48]2 years ago
7 0
One end increases and one end decreases because log2=0.3 and if you multiply that by the leading coefficient, 4, you will get 1.2. Because the new leading coefficient, 1.2, is positive, one end goes up and another end goes down. 
Gennadij [26K]2 years ago
3 0

Answer:

One end increases and one end decreases

Step-by-step explanation:

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What is the domain of the function f(x)= e^x/e^x+c if c is a constant greater than 0
Viktor [21]

Answer: Option d.

Step-by-step explanation:

To find the domain of the function we should look for the values for which the denominator is equal to zero, because the division by zero is not allowed.

We know by definition that the function e^x is always greater than zero for all <em>x</em>.

We know that the constant <em>c</em> is greater than zero (c>0).

Then, the expression e^x+c is never equal to zero.

Therefore, it does not exist a value for <em>x</em> that makes the denominator 0. Then, the domain of the function is all real numbers.

The answer is the option d.

3 0
3 years ago
3/x+1 -1/2 = 1/3x+3 please help solve
mash [69]
\frac{3}{x+1}^{(6}-\frac{1}{2}^{(3x+3}=\frac{1}{3x+3}^{(2} \\\\ 18-3x-3=2 \\\\ -3x+15=2\\\\ -3x=2-15 \\\\-3x=-13 \\\\ \boxed{x=\frac{13}{3}}
4 0
2 years ago
The sides of a rectangle are 6.3 cm and 4.8cm, each correct to 1 decimal place.
Effectus [21]
Error= 0.1/2, 0.05

4.8 + 0.05 = 4.85
6.3 + 0.05 = 6.35

4.85 x 6.35 = 30.7975 cm (when rounded, gives 30.80 cm).
8 0
3 years ago
(7 points) Cars arrive at a toll both according to a Poisson process with mean 80 cars per hour. If the attendant makes a two-mi
saveliy_v [14]

Answer:

The probability that at least 1 car arrives during the call is 0.9306

Step-by-step explanation:

Cars arriving according to Poisson process - 80 Cars per hour

If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67   X ≅ Poisson (λ = 2.67)

Now, we find the probability: P(X≥1)

P(X≥1) = 1 - p(x < 1)

P(X≥1) = 1 - p(x=0)

P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!

P(X≥1) = 1 - e^-2.67

P(X≥1) = 1 - 0.06945

P(X≥1) = 0.93055

P(X≥1) = 0.9306

Thus, the probability that at least 1 car arrives during the call is 0.9306.

5 0
2 years ago
If y-x=4 and x is three times the value of y, what is the value of x + y?
Eduardwww [97]

Answer:

E = 8

Step-by-step explanation:

y - x = 4

y - (3y) = 4

y - 3y = 4

2y = 4

y = 4/2

y = 2

x = 3y

x = 3×2

x = 6

x + y = 2+6

x+y = 8

6 0
2 years ago
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