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Y_Kistochka [10]
3 years ago
7

Raymond works in a appliance store and gets a 12 percent discount price.the original cost of a video game system is 175$.

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

12% = 0.12

175 x 0.12 = 21

175-21 = $154 

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1:2. Two hexagons fit in a hexagon.
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Fracción equivalente 1/10
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2/20 is equivalent to 1/10 because 2/2 is equal to 1 and 20/2 is equal to 10.
6 0
3 years ago
What is 18+5-y.this is first question
UkoKoshka [18]

<u><em>Answer:</em></u>

y = 23

<u><em>Step-by-step explanation:</em></u>

Add the numbers:

18 + 5 - y

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8 0
3 years ago
Find the volume of the triangular prism in the picture shown. Round your answer to the
Olenka [21]

Given:

A figure of a triangular prism.

Height of triangular base = 9\dfrac{2}{3} yd

Base of triangular base = 4 yd

Height of prism = 4 yd.

To find:

The volume of the triangular prism.

Solution:

Volume of a triangular prism is:

V=Bh              ...(i)

Where, B is the area of triangular base and h is the height of the prism.

Area of triangular base is:

B=\dfrac{1}{2}\times base\times height

B=\dfrac{1}{2}\times 4\times 9\dfrac{2}{3}

B=2\times \dfrac{29}{3}

B=\dfrac{58}{3}

Putting B=\dfrac{58}{3} and h=4 in (i), we get

V=\dfrac{58}{3}\times 4

V=\dfrac{232}{3}

V=77.33...

V\approx 77.3

The volume of the triangular prism is 77.3 cubic yards. Therefore, the correct option is 2.

4 0
3 years ago
4. Amazon executives believe that at least 70% of customers would return a product 2 days after it arrives at their home. A samp
inysia [295]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • Sample of 500 customers, hence n = 500.
  • Amazon believes that the proportion is of 70%, hence p = 0.7

The <u>mean and the standard error</u> are given by:

\mu = p = 0.7

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.7(0.3)}{500}} = 0.0205

The probability is the <u>p-value of Z when X = 0.68</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.68 - 0.7}{0.0205}

Z = -0.98

Z = -0.98 has a p-value of 0.1635.

0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

A similar problem is given at brainly.com/question/25735688

7 0
2 years ago
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