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3241004551 [841]
3 years ago
6

FAST PLEASE HELP MEEE: At a certain high school, 35 students play only stringed instruments, 10 students play only brass instrum

ents, and 5 students play both. There are also 5 students who play neither stringed nor brass instruments. what is the probability that a randomly selected student plays either a string or brass instrument?
P(AUB)={?}
Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

35=10+5+5+p

35=20+p

35-20=p

p=15

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Glad you ask!!!

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3 years ago
Compute the sum<br><br> a. 3,577<br><br> b. 7,161<br><br> c. 1,792<br><br> d. 1,785
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6 0
2 years ago
What is the percent of change in 6 yards to 36 yards
BaLLatris [955]

Answer:

The percent of change in 6 yards to 36 yards is 500% .

Step-by-step explanation:

Formula

Percentage = \frac{Change\ in\ value\times 100}{initial\ value}

Where

Change in value = Final value - initial value

As given

The percent of change in 6 yards to 36 yards.

Final value = 36 yards

initial value = 6 yards

Change in value = 36 - 6

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Put in the formula

Percentage = \frac{30\times 100}{6}

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Therefore the percent of change in 6 yards to 36 yards is 500% .


3 0
4 years ago
Read 2 more answers
Help! 0.246..... as a fraction in simplest form ??
lutik1710 [3]
0.246 can be written as 246/1000
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8 0
3 years ago
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