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Xelga [282]
3 years ago
9

How many 2X4 foot tiles are needed for 48 square feet?

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

Answer:

The number of  (2 X 4 ) foot tiles  needed for 48 square feet is 6.

Step-by-step explanation:

The dimensions of the small tiles =  2 ft x 4 ft

Area that needed to be covered by tiles = 48 sq feet

Now, Area of 1 tile  = LENGTH X WIDTH

                                 = 2 ft x 4 ft = 8 sq ft

Now, \textrm{Total  number of tiles required to cover the area}  = \frac{\textrm{Total Area that needs to be covered}}{\textrm{Area of each tile}}

= \frac{48 sqft}{8sqft}   = 6

or, Number of tiles required = 6

Hence, the number of  (2 X 4 ) foot tiles  needed for 48 square feet is 6.

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What is the approximate area of a sector given O= 56 degrees with a diameter of 12m?​
jeyben [28]

Area of sector is 17.584 meters

<em><u>Solution:</u></em>

Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m

Diameter = 12 m

Radius = Diameter / 2 = 6 m

An angle of  56 degrees is the fraction \frac{56}{360} of the whole rotation

A sector of a circle with a sector angle of 56 degrees is therefore also the fraction \frac{56}{360} of the circle

The area of the sector will therefore also be  \frac{56}{360} of the area

\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584

Thus area of sector is 17.584 meters

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3 years ago
5. Algebra Write an expression you can
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Answer:

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Step-by-step explanation:

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How to solve multi step inequality
iVinArrow [24]

Answer:

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5 0
3 years ago
On Friday 237 people attended film festival.there r more 446 people who attended on Saturday than Friday .liza says that a total
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Liza is wrong because...

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4 0
3 years ago
A sample of 10 adult elephants had an average weight of 12,556 pounds. The standard deviation
kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.25

The margin of error is:

M = T*s = 3.25*25 = 81

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

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