Domain of f(x) = √6 - 2x is {x | -∞ < x ≤ 3}
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
There are 30 halves in 15, plus the extra half
Step-by-step explanation:
= 31 / 2; 31 / 2 times 3 / 4 = 93 / 8 = your answer. Hope this helps
Answer:
The new position of point M' (-2, -1) after Rotation of 90° Clockwise
Step-by-step explanation:
Given that,
diagram of given scenario is shown below.
From the Question,
There is a triangle ΔP which is Rotated by 90° clockwise about the point
(2, -1)
Let says the given point M (2, -1).
Rotation of point through 90° about the origin in clockwise direction when point M (h, k) is rotated about the origin O through 90° in clockwise direction. The new position of point M (h, -k) will become M' (-h, -k).
So, The new position of point M' (-2, -1) after Rotation of 90° Clockwise.