Answer:
Step-by-step explanation:
From the given information:
Let represent 
as the first player getting an ace
Let 
to be the second player getting an ace and
as the second player not getting an ace.
So;
The probabiility of the second player not getting an ace and the first player getting an ace can be computed as;
Let's determine the probability of getting an ace in the first player
i.e
To determine the probability of the second player getting an ace and the first player getting an ace.
Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:
Therefore;
for n= 2
for n= 10
for n = 100
Given data is that circles are identical. According to this diameters are identical too.
Diameter of the first circle is 4x and for the second 2x+3.
We can make equality 4x = 2x+3 => 2x=3 => x=3/2
Circumference of each circle is C= 2r pi = 2*(3/2) pi = 3 pi
The correct is fifth answer.
Good luck!
You have 1/5x and 4/5x if you add these you get 5/5x or 1x
The left side simplifies to:
x +9 > -11
Subtract 9
x > -20
The answer to your question is 260
