$2m^2 +2m-12=0 \ /:2\\ \\m^2+m-6=0\\ \\m^2+3m-2m-6=0\\ \\m(m+3)-2(m+3)=0\\ \\(m+3)(m-2)=0\\ \\m+3=0\ \ \ \vee\ \ \ m-2=0\\ \\.\ \ \ \ m=-3\ \ \ \ \ \ \ \ \ \ \ \ m=2$

6 0

3 years ago

Write an equation of a line parallel to the line y=-2x+8 and passes through the point (-1,-3)

saul85 [17]

Answer: y=–2x–5

Step-by-step explanation:

The equation of a straight line:

y=mx+c

m must be the same for the two lines to be parallel.

y=mx+c

y=–2x+8 → m=–2

For a new equation:

x=–1, y=–3, m=–2, c=?

y=mx+c → –3=–2×(–1)+c

–3=2+c

c=–5

So:

y=–2x–5

5 0

3 years ago

IMANU PAYS 30 EACH MONTH FOR HIS GYM MEMBERSHIP WHAT IS THE CHANGE IN THE AMOUNT OF MONEY IN HIS ACCOUNT AFTER 2/3 OF YEAR

likoan [24]

240 is the answer to your question

4 0

3 years ago

Solve 10 (2y +2) - y =2 (8y- 8)

Jet001 [13]

The answer is y = −12

8 0

3 years ago