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jonny [76]
3 years ago
5

7.

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

B. {–3, 5.9, 8.3}

Step-by-step explanation:

The domain is the set of all the values of  

x .The range is the set of all the values of  y .

Domain: { 3.2 , 7.6 , 1.4 , − 9.1 }

Range: { − 3 , 5.9 , 8.3 }

Answer:

range is -3, 5.9 , 8.3

Step-by-step explanation:

{(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}

We are given with set of ordered pairs (x,y)

In each ordered pair, x is the domain and y is the range

for domain , take all the x  values (first number) from the ordered pairs

for range, take all the y value (second number) from the ordered pairs

y values of the ordered pairs are -3, 5.9, -3, 8.3

So range is -3, 5.9 , 8.3

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Step-by-step explanation:

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Some one help me on this please !!
Galina-37 [17]

Answer:

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6 0
4 years ago
Gabriel deposits $2,500 into each of two savings accounts.
charle [14.2K]

Answer:

$5,612.16

Step-by-step explanation:

Part 1) Account I earns 4% annual simple interest.

we know that

The simple interest formula is equal to

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

substitute in the formula above

Part 2) Account II earns 4% interest compounded annually.

we know that    

The compound interest formula is equal to  

A=P(1+rt)

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3 years

p=$2,500

r=4%=4/100=0.04

substitute in the formula above  

A=2,500(1+0.04 * 3)

A=2,500 (1.12)

A=$2,800

Part 3) What is the sum of the balances of Account I and Account II at the end of 3 years?

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8 0
4 years ago
I need the answers to questions 1&2
Leokris [45]

Answer:

see explanation

Step-by-step explanation:

(1)

the sine of an angle = \frac{opposite}{hypotenuse}

(a)

here the opposite is 12 and the hypotenuse is 13

12 is the side opposite ∠DEF ← required angle

(b)

the tangent of an angle = \frac{opposite}{adjacent}

here the opposite is 5 and the adjacent is 12

∠DFE ← required angle

(2)

to calculate AB use Pythagoras' identity in the right triangle

AB² = 2² + 3² = 4 + 9 = 13, hence

AB = \sqrt{13} ≈ 3.6 ( to nearest tenth )

tanB = \frac{2}{3} ⇒ B = 33.7°

tanA = \frac{3}{2} ⇒ A = 56.3°





5 0
3 years ago
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