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3 years ago

7.

Mathematics

1 answer:

nika2105 [10]3 years ago

3 0

Answer:

B. {–3, 5.9, 8.3}

Step-by-step explanation:

The domain is the set of all the values of

x .The range is the set of all the values of y .

Domain: { 3.2 , 7.6 , 1.4 , − 9.1 }

Range: { − 3 , 5.9 , 8.3 }

Answer:

range is -3, 5.9 , 8.3

Step-by-step explanation:

{(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}

We are given with set of ordered pairs (x,y)

In each ordered pair, x is the domain and y is the range

for domain , take all the x values (first number) from the ordered pairs

for range, take all the y value (second number) from the ordered pairs

y values of the ordered pairs are -3, 5.9, -3, 8.3

So range is -3, 5.9 , 8.3

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A bridge hand is made up of 13 cards from a deck of 52. find the probability that a hand chosen at random contains at least 3 ki

Vlad [161]

1.
In total there are C(52, 13) ways that we can pick a hand, that is $\frac{52!}{13!39!}$

2.
P(a hand contains at least 3 kings)
=P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

3.
first let's find P(a hand contains exactly 3 kings):

P(a hand contains exactly 3 kings)
=n(a hand contains exactly 3 kings)/C(52, 13)

n(a hand contains exactly 3 kings)=C(4, 3)*C(48, 10)

where C(4,3) is the total number of ways we can pick 3 out of 4 kings,

C(48, 10) is the number of picking 10 letters to complete a hand, out of the 52-4=48 non-king cards.

so P(a hand contains exactly 3 kings)=[C(4, 3)*C(48, 10)]/C(52, 13)

4. with the same reasoning as in step 3:

P(a hand contains 4 kings)=n(a hand contains 4 kings)/C(52, 13)

= [C(4, 4)*C(48, 9]/C(52, 13)

5.

P(a hand contains at least 3 kings)
=P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

=[C(4, 3)*C(48, 10)]/C(52, 13)+ [C(4, 4)*C(48, 9)]/C(52, 13)

= $\frac{C(4, 3)*C(48, 10)+C(4, 4)*C(48, 9)}{C(52, 13)}$

= $\frac{4* \frac{48!}{10!38!} + \frac{48!}{9!39!}}{ \frac{52!}{13!39!} }$

simplify by 38! in the denominators and 48! in the numerators :

$\frac{4* \frac{1}{10!} + \frac{1}{9!39}}{ \frac{52*51*50*49}{13!39} } 

$

now simplify by 9! in all denominators:

$\frac{ \frac{4}{10}+ \frac{1}{39} }{ \frac{52*51*50*49}{13*12*11*10*39}}$

$\frac{ 0.426 }{ 9.7} =0.044$

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4 years ago

2(x - 3) + 5x < 9x - 14<br> how do you solve this

VARVARA [1.3K]

Answer:

x>4

Step-by-step explanation:

Use the distributive property to multiply 2 by x−3.

2x−6+5x<9x−14

Combine 2x and 5x to get 7x.

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Subtract 9x from both sides.

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Combine 7x and −9x to get −2x.

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Add 6 to both sides.

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Add −14 and 6 to get −8.

−2x<−8

Divide both sides by −2. Since −2 is <0, the inequality direction is changed.

x>-8/-2

Divide −8 by −2 to get 4.

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