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Mademuasel [1]
3 years ago
5

Can yall plz help me on this ???

Mathematics
2 answers:
vodka [1.7K]3 years ago
8 0
A is the correct answer to this problem.
Stolb23 [73]3 years ago
4 0

Answer:

its the first one

Step-by-step explanation:

just use photomath (plus is free rn so you can see the steps)

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you buy butter 4.13 a pound one portion of onion requires 1.7 oz of butter how much dose the butter for one portion cost
yuradex [85]

Answer:

<u>The butter for one portion of onion costs $ 0.44</u>

Step-by-step explanation:

Let's recall that 1 pound = 16 ounces, therefore we have:

Cost of one pound of butter = $ 4.13

Cost of sixteen ounces of butter = $ 4.13

How much dose the butter for one portion cost?

We can use Direct Rule of Three for answering this question, as follows:

Ounces       Cost

  16                4.13

  1.7                   x

**************************

16x = 4.13 * 1.7

16x = 7.021

x = 7.021/16

x = 0.44 (Rounding to the next cent)

<u>The butter for one portion of onion costs $ 0.44</u>

5 0
3 years ago
Inequalities <br><img src="https://tex.z-dn.net/?f=%20-%205%20%5Ctimes%20%20%2B%202%20%5Cgeqslant%20%20-%2048" id="TexFormula1"
Andrej [43]

\bf -5x+2\geqslant -48\implies -5x \geqslant -50\implies \stackrel{\textit{now, we're dividing by -5}}{\cfrac{-5x}{-5}\stackrel{\stackrel{\downarrow }{\frac{}{}}}{\leqslant}\cfrac{-50}{-5}}\implies x\leqslant 10

5 0
3 years ago
Solve the system of equations by substitution.<br> y = 8<br> X – 2y + 3z = 3<br> 3x + 3y – 2z = 15
Dafna1 [17]

Answer:

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve using either method. This is shown

in the following examples.

Example 1.

3x +2y − z = − 1

− 2x − 2y +3z = 5 We will eliminate y using two different pairs of equations

5x +2y − z = 3

Step-by-step explanation:

6 0
3 years ago
Which of the following is a solution for 5 - 2xs-3?<br> -4<br> 4<br> 1<br> -1
liq [111]
I want to say -1. if you first combine like terms the equation would look like 2-2x. then next step i did was divide both sides by negative 2 to get the x by itself. after i did that i got -1 x.
5 0
2 years ago
Can someone please find the inverse and explain step by step
d1i1m1o1n [39]

Answer:

.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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