Hello,
p="the point is in the first quadrant"
q=" its coordinates are positive"
Your theorem is p==>q
The converse of the theorem is q==>p
(if a point has its coordinates positive then he is in the first quadrant)
Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
Answer:
y=2x/5-4x
Step-by-step explanation:
multiply z-4y on both sides,match the Ys together and then make y common
Answer:
-4.3375796178343949044585987261146
Step-by-step explanation:
you can probably round it off but that is what my calculator gave me.
