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3 years ago

On the coordinate plane below , quadrilateral 1 has been transformed to form quadrilateral 2?

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

1 and 5

Step-by-step explanation:

because the math

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Find the real number root

Hunter-Best [27]

Answer:

No real roots.

Step-by-step explanation:

Unless you guys are dealing with imaginary numbers, you cannot take the square root of a negative.

7 0

3 years ago

Please help me!!! Geometry question.

tigry1 [53]

Answer:

The volume of the figure is $(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}$

Step-by-step explanation:

we know that

The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid

step 1

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=\frac{l\sqrt{2}}{2}\ units$ ----> the diagonal of the square base of pyramid is equal to the diameter of the cone

$h=l\ units$

substitute

$V=\frac{1}{3}\pi (\frac{l\sqrt{2}}{2})^{2}(l)$

$V=\frac{1}{6}\pi (l)^{3}\ units^{3}$

step 2

Find the volume of the square pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the base

h is the height of the pyramid

we have

$h=l\ units$

$B=l^{2}\ units^{2}$

substitute

$V=\frac{1}{3}l^{2}(l)$

$V=\frac{1}{3}l^{3}\ units^{3}$

step 3

Find the volume of the figure

$\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}$

5 0

3 years ago

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

3 years ago

The perimeter of the figure below is 141.8ft. Find the length of the missing side

Irina18 [472]

Answer:8.6

Step-by-step explanation:

The easiest way to do this is for you to subtract all the sides from the total perimeter since the perimeter is all of the sides added and your remainder is your answer

Hope this helps

7 0

3 years ago

Read 2 more answers

The width of a rectangle is 8 inches longer than its length. The perimeter is 104 inches.

Vesna [10]

Answer:

The width of the rectangle is 56 and the length is 48

Step-by-step explanation:

divide the perimeter in half (52 + 52)

then subtract 4 from one of the 52's

you get the answer of 56 and 48

Your answer can be checked by conferming that 56 - 48 = 8 so the width of a rectangle is 8 inches longer than its length.

6 0

3 years ago

Read 2 more answers