Answer:
A≈113.1
Step-by-step explanation:
A=1
4πd2=1
4·π·122≈113.09734
Answer:
The answer is 20
Step-by-step explanation:
(Edge2020)
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
The answer is 15
Step-by-step explanation:
You just have to multiply angle BC times angle AC to have the answer because angle AB is verticle to angle BD.
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange x + 5y = 10 into this form
Subtract x from both sides
5y = - x + 10 ( divide all terms by 5 )
y = - 
x +2 ← in slope- intercept form
with slope m = -
• Parallel lines have equal slopes, hence
y = - x + c ← is the partial equation of the parallel line
To find c substitute (1, 3) into the partial equation
3 = - + c ⇒ c = 
y = - x + ← equation of parallel line
