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qaws [65]
3 years ago
5

Write the smallest possible odd number with all the following dight 5,2,3,7.​

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

2357

Step-by-step explanation:

You might be interested in
On a recent homework assignment, Eli needed to solve the equation
tamaranim1 [39]

Answer:

A - the real answer is 7

Step-by-step explanation:

g²=49 (square root 49 to get 7)

B) not sure - possibly wrote the negative sign as a mistake

7 0
3 years ago
Jerry's Seed Palace claims that 80% of its lima bean seeds will germinate. Suppose the company's claim is true. Callie buys a pa
Mekhanik [1.2K]

Answer:

A

Step-by-step explanation:

This is a Bernoulli trial problem.

Since the probability that the seed will germinate is 80% or 0.8, the probability that they won’t germinate is 0.2

Now let’s say the probability to germinate is p and the probability not to is a, we can now set up the Bernoulli equation in this regard. Since we are proposing that exactly 14 will germinate, it means 6 are not expected to germinate

P(14) = 20C14 (0.8)^14 (0.2)^6 = 0.109099700973

Option A is the right answer

3 0
3 years ago
Whats the value of x
fiasKO [112]

Answer:

x=14

Step-by-step explanation:

you should set up your problem like this:

5x=3x+28

use order of operations aka PEMDAS to solve

you're answer is 14

8 0
2 years ago
If f(x) = x^4-x^3+x^2 and g(x)= -x^2, where x does not = 0, what is (f/g)(x)?
Korvikt [17]

For this case we have the following functions:

f (x) = x ^ 4-x ^ 3 x ^ 2\\g (x) = - x ^ 2

By definition of composition of functions we have to:(f \ g) (x) = \frac {f (x)} {g (x)}

So:

\frac {f (x)} {g (x)} = \frac {x ^ 4-x ^ 3 x ^ 2} {- x ^ 2} = \frac {x ^ 4} {- x ^ 2} +\frac {-x ^ 3} {- x ^ 2}+ \frac {x ^ 2} {- x ^ 2} =

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

\frac {f (x)} {g (x)} = - x ^ 2+x-1

ANswer:

(\frac {f} {g}) (x) = - x ^ 2 +x-1

3 0
3 years ago
Describe how to transform:
Anna71 [15]

Answer:

x^\frac{35}{6}

Step-by-step explanation:

The expression to transform is:

(\sqrt[6]{x^5})^7

Let's work first on the inside of the parenthesis.

Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:

\sqrt[n]{a} = a^{\frac{1}{n}}

Therefore \sqrt[6]{a} = a^{\frac{1}{6}}

Now let's replace a with x^{5} which is the algebraic form we are given inside the 6th root:

\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}

Now use the property that tells us how to proceed when we have  "exponent of an exponent":

(a^n)^m= a^{n*m}

Therefore we get:  (x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}

Finally remember that this expression was raised to the power 7, therefore:

[tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}[/tex]

An use again the property for the exponent of a exponent:

8 0
2 years ago
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