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AlekseyPX
2 years ago
11

Whats the value of x

Mathematics
1 answer:
fiasKO [112]2 years ago
8 0

Answer:

x=14

Step-by-step explanation:

you should set up your problem like this:

5x=3x+28

use order of operations aka PEMDAS to solve

you're answer is 14

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What is the value of n when 6n-14=3n+7
Goshia [24]

answer: n=7

work:

6n-14=3n+7

6n-14 (+14) = 3n+7 (+14)   add 14 to both sides

6n=3n+21

6n(-3n)=3n(-3n)+21    subtract 3 from both sides

3n=21

3n/3= 21/3    divide by 3 on both sides

n=7

6 0
4 years ago
Read 2 more answers
1. Which is a linear equation?<br> Pls help asap
Rama09 [41]
X2 = y

i believe :)
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3 0
2 years ago
Read 2 more answers
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
A dealer earns a profit of 8$ per bag of white cement and a loss of 5$ per bag of grey cement.
Natali [406]

Answer :-

  1. loss = <em> </em><em>100</em><em>0</em><em>$</em><em> </em>
  2. 4000

Step by step explanation :-

1#

Profit on 3000 bags of white cement sold = 3000 × 8 = 24000

loss on 5000 bags of grey cement sold = 5000 × 5 = 25000

<u>Alternatively</u><u>:</u><u> </u>

  • Net loss = ( 25000 - 24000 ) = 1000$
  • profit/ loss = $ [3000 × 8 - 5000 × 5 ]
  • $ [24000 - 25000]
  • -1000$

<em>As</em><em> </em><em>the</em><em> </em><em>result</em><em> </em><em>of</em><em> </em><em>transaction</em><em> </em><em>is</em><em> </em><em>negative</em><em>/</em><em> </em><em>loss</em><em> </em>

  • Loss = 1000$

2#

  • Loss on the scale of 6400 grey bags = 6400 × 5 = 32,000

<em>In</em><em> </em><em>order</em><em> </em><em>to</em><em> </em><em>have</em><em> </em><em>no</em><em> </em><em>profit</em><em>, </em><em> </em><em>profit from the </em><em>Cello </em><em>white cement should be 32</em><em>0</em><em>0</em><em>0</em><em>.</em><em> </em>

  • Number of white cement bags to be sold = 32000 / 8 = 4000

<em>4000 why cement bags and 6400</em><em> </em><em>grey</em><em> </em><em>cement</em><em> </em><em> </em><em>bags</em><em> </em><em>are sold in order to have no profit and </em><em>n</em><em>o</em><em> </em><em>loss </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>~</em>

5 0
2 years ago
Susan throws a softball upward into the air at a speed of 32 feet per second from a 88 dash foot88-foot platform. the distance u
Rudiy27
D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft

2] <span> how many seconds does it take to reach the ground after first being thrown​ upward? ​
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec


</span>
3 0
4 years ago
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