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3 years ago

What is the volume, in cubic M, of a cylinder with a height of 13M and a base radius of 3M, to the nearest 10th Place?

Mathematics

2 answers:

mixas84 [53]3 years ago

8 0

Answer:

367.6 m³

Step-by-step explanation:

h=13 r=3 identify variables

V= πr² h use volume of a cylinder formula

V=π(3)²(13) substitute variables into formula

V= 367.56634047 multiply

V=367.6 m³ round to the nearest tenths place

irina [24]3 years ago

7 0

Answer:

The volume of the cylinder is 367.6 M^3

Step-by-step explanation:

Mathematically, we have the volume of a cylinder calculated as follows;

V = pi * r^2 * h

r is the base radius given as 3 m

h is the height given as 13 m

So, we have the volume as;

V = 22/7 * 3^2 * 13 = 367.6 M^3

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1 year ago

Some wolves howl in the woods. 12 wolves join them. Now 30 wolves howl. How many wolves howled at first?

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2 years ago

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The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31

4 0

3 years ago