All categories

3 years ago

Ms. Sze is grading math tests. A student’s work on a problem is given below

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

Answer:

No the student is not correct because the answer is 0.4761. All the student did was wrong was the adding up the zeros.

Step-by-step explanation:

You might be interested in

In the past month, Tammy rented 1 video game and 3 DVDs. The rental price for the video game was $2.20. The rental price for eac

Zepler [3.9K]

Answer:

$9.60

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Write each sum as a product of two factors for 6•7+3•7

lapo4ka [179]

65 is the product of this

6 0

3 years ago

Xavier collected 12 shells at the beach. Nora collected 5 fewer than Xavier. How many shells did Nora collect?

Ulleksa [173]

Answer:

7, Nora collected 7 shells.

Step-by-step explanation:

Xavier collected 12 shells whilist she collected 5 fewer then Xavier.

12 - 5 = 7

Therefore, Nora collected 7 shells at the beach.

8 0

3 years ago

If you wanted to make the graph of y = 8x - 10 less steep, as well as shift the

azamat

Answer:

4x-15=y

Step-by-step explanation:

The higher the rise over the run the more steep your slope will be thus 4x is less steep than 8x because it does not rise as much.

The y intercept shifted downward means anything (-10>b) can be plausible for b.

3 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago