Step-by-step explanation:
The line is
j --------K----------M---------N---------L
6. 4. 4. 4
JN = 14
KM = 4
KM = MN = LN =4
JK = 14 - (KM+MN)
JK = 14 - 8 = 6
JK = 6
MN = 4
LJ = 18
KN = 8
MJ = 10
NL = 4
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
Answer:
Step-by-step explanation:
Perform the indicated multiplication first:
25000 - 500bx + 50ax - abx²
It would seem that this should be part of an equation, and that the other part is missing; without another part, there's no way to determine the values of a and b. Please ensure you have copied this problem down completely.
Answer:
4
Step-by-step explanation:
since y=mx+c
comparing the question with the above equation
m=4 and c= -5
