Answer:
vertex = (- 2, - 36)
Step-by-step explanation:
Given a parabola in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= - 
f(x) = 5x² + 20x - 16 is in standard form
with a = 5, b = 20 and c = - 16
= -
= - 2
Substitute x = - 2 into f(x) for corresponding y- coordinate
f(- 2) = 5(- 2)² +20(- 2) - 16 = 20 - 40 - 16 = - 36
vertex = (- 2, - 36)
Answer:
Step-by-step explanation:
Answer:
C and D
Step-by-step explanation:
5^3 - 5^0 = 125 - 1 = 124, so it's not A
5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B
5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C
5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D
5 + 5^2 = 5 + 25 = 30, so it can't be E