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Andrews [41]
2 years ago
15

Classify each as a minor arc, major arc, or semicircle!!!!!!!!!!!!

Mathematics
1 answer:
KatRina [158]2 years ago
8 0

Answer:

Minor Arc: AE, FA

Semicircle: AEB, FDE

Major Arc: FED, BDF

Step-by-step explanation:

Required

Classify base on the type or arc

<u>Keynote</u>

Minor arcs are less than 180 degrees

Semicircle are equal to 180 degrees

Major arcs are less than 180 degrees

Using the above keynote, we have the following observation

AE: Minor

AEB: Semicircle

FDE: Semicircle

FED: Major

FA: Minor

BDF: Major

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63

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Step-by-step explanation:

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Sara is shopping for jeans and shirts on tax-free weekend. She has $60 to spend. She knows she will buy one pair of jeans for $2
Neko [114]

Answer:29x+10y<60

Step-by-step explanation:

She has $60 to spend.

And no tax. it should be 29x+10y>(less than or equal to) $60.

6 0
2 years ago
Scientific notation of 47300
Reil [10]
4.7 x 10^4
or 5 x 10^4

<span>The scientific notation of 70, 030, 000. To find the scientific notation of this value </span><span><span>
1.  </span>We first move the period which separates the whole number from the decimal number which is located after the numbers of the given value.</span> 
<span><span>2.  </span>We move it in the very recent order number which is seventy million, seven and zero.</span> <span><span>
3.  </span>It becomes 7.003</span>
<span><span>4.  </span>Thus we count how many moves we did from the tens to the ten million order place.</span> <span><span>
5.  </span>7.003 x 10^7 </span>


6 0
3 years ago
One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W
Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be '\text{B}_i'.

This means that the cell will get killed if \text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5 happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P(\text{B}_1) = 0.2, P(\text{B}_2) = 0.4, P(\text{B}_3) = 0.3, P(\text{B}_4) = 0.6, P(\text{B}_5) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= 1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]

P(A) = 1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]

P(A) = 1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

4 0
3 years ago
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