Answer:
p = -4, q = -3
Step-by-step explanation:
y = -2x +4 ... (1) perpendicular bisector of AB, slope = -2
slope of AB = 1/2
Line AB pass (8,3): (y-3) / (x-8) = 1/2
AB equation: y-3 = 1/2(x-8) y = 1/2x - 1 ... (2)
(2)-(1): 5/2 x = 5 x = 2
y = 0 (2,0) intercept of bisector and AB, it is midpoint of A (8,3) and (p,q)
(8+p)/2 = 2
<u>p = -4</u>
(3+q)/2 = 0
<u>q = -3</u>
Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
Answer:
y=4x + 3/4
Step-by-step explanation:
