Question

1

Answer 1

Step-by-step explanation:

f°g=$f(g(x))$

$g(x)=x^2-6x$

$f(x)=1/x$

$f(g(x))=$$\frac{1}{x^2-6x}$

if the denominator is zero the number is undefined which makes it not in the domain of the function

set $x^2-6x$ equal to 0

the values for x is 0 or 6

so the only value that is not in the domain of f°g is 0 and 6

Hope that helps :)