9. 10x + 5y is the equation for larger watermelons + smaller watermelons (you did not provide information about the medium watermelons, so we must assume given the options you miswrote one of them). We can hold NO MORE than 500 pounds, so 10x + 5y must be smaller than 500. The best answer is C assuming that "5y" represents your "Medium Watermelons"- because smaller watermelons are stated to be 5 and medium ones should therefore be between 5 and 10, the option provided by A wouldn't make since because 3 pounded watermelons are not "medium" in comparison to the "small ones" that are heavier/bigger. Your best option is C, 10x + 5y < 500, the exact answer technically would be 10x + 5y <= 500.
That is an annuity and use the attached formula.
Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 *
<span>
<span>
<span>
1.8020924036
</span>
</span>
</span>
-1 /.055 -300
Total = 300 *
<span>.8020924036 / .055 - 300
</span>Total = 300 *
<span>
<span>
<span>
14.5834982473
</span>
</span>
</span>
-300
Total =
<span>
<span>
<span>
4375.0494741818
</span>
</span>
</span>
-300
Total =
<span>4075.05
</span>
Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>
Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be
inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment
be a height on side
. Since this triangle is equilateral, the size of each internal angle will be
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
<h3>Area of of the circle that is not covered</h3>
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is
inches, the radius of this circle will also be
inches.
The area (in square inches) of a circle of radius
inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.
1 and 1/2 is the scale factor
Your answer is attached to the pic