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-Dominant- [34]
4 years ago
14

I need help with this. i will add you as a brillance if you get this right

Mathematics
1 answer:
Crank4 years ago
7 0

Answer:

i think its b and c

Step-by-step explanation:

8x+7+4x and 12x+7 are the same just not simplified

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You are getting a line-up ready for a school kickball game. You have 7 girls and 7 boys. The rules state each child must kick th
Effectus [21]

Answer:

50,803,200 ways

Step-by-step explanation:

In this situation, since you should alternate girl-boy or boy-girl, the line-up can either start with a boy or a girl kicking which would yield one of the two following patterns:

BGBGBGBGBGBGBG or GBGBGBGBGBGBGB.

For each of those patterns, there are 7! ways to arrange all boys and 7! ways to arrange all girls. The number of ways that a line-up can be made for one round of kicking is:

n=2*7!*7!\\n=2*(7*6*5*4*3*2)^2\\n=50,803,200\ ways

There are 50,803,200 ways to set the line-up.

8 0
4 years ago
Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and
balu736 [363]

Answer:

(a) The sample size required is 43.

(b) The sample size required is 62.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

 CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

(a)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 72 seconds = 1.2 minutes

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1.2}]^{2}\\\\=42.684\\\\\approx 43

Thus, the sample size required is 43.

(b)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 1 minute

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1}]^{2}\\\\=61.4656\\\\\approx 62

Thus, the sample size required is 62.

3 0
3 years ago
Trevor deposits $1500 in a simple interest account that pays 4.3% annually. After 15 years, how much total money would be in the
andrezito [222]

Answer:

$2467.50 would be in the account after 15 years.

4 0
3 years ago
Read 2 more answers
Plsplspls help!!!
RideAnS [48]

Answer:

a) the answer if the substitute is 300

7 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
bogdanovich [222]

Answer:

I believe the answer is 39.368, if we round that it makes it, 39.4

Step-by-step explanation:

5 0
3 years ago
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