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3 years ago

Which of the following is an example of the associative property?

Mathematics

2 answers:

Mashutka [201]3 years ago

6 0

Associative property is when you move the grouping symbols: ( and )
So the answer is B.

labwork [276]3 years ago

6 0

A associative graph is when you are going to be moving the grouping symbols. So B) <span>-7 + (19 + 5) = (-7 + 19) + 5</span>

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If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

iren [92.7K]

Answer: The value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

Step-by-step explanation:

Given: $f(x) = 4x^2 \text { and } g(x) = x+1$

To find: $(f_\circ g)(x)$

As we know it is composition function which means that g(x) function is in f(x) function.

So we have

$(f_\circ g) (x) = f[g(x)]$

$\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2$

Now substitute the value of g(x) we get

$(f_\circ g)(x)= 4(x+1)^2$

Hence, the value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

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3 years ago

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kati45 [8]

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3 years ago

Equation for= Y=x shift the graph up 5 units

telo118 [61]

Answer:

y = x + 5

Step-by-step explanation:

The graph of the ramp function y = x is a straight line with slope +1 and passing through the origin. If the whole graph is shifted up 5 units, the equation/function becomes

y = x + 5. The resulting graph is parallel to y = x.

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3 years ago

Solve for x <br> This is also an octagon if it helps!

Karo-lina-s [1.5K]

Answer:

x = 10

Step-by-step explanation:

it has 8 sides so:

total interior angle degrees = (180° x 8 sides) - 360° = 1080°

11x + 14 + 4x + 87 +2x + 70 + 4x + 31 + x + 92 + 3x + 167 + 5x + 48 + 2x + 251 = 1080°

combine like terms:

32x + 760° = 1080°

subtract 760° from both sides of the equation:

32x = 320°

divide both sides by 32:

x = 10

8 0

3 years ago

What line is parallel to 2x+5y=6 that goes through (5,3)

Anna11 [10]

Answer:

4y = x - 17

Step-by-step explanation:

First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = $\frac{-2x}{5}$ + $\frac{6}{5}$ which make the gradient, m, the coefficient of x = $\frac{-2}{5}$ . Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)

Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)

y - 3 = $\frac{1}{4}$ (x - 5); y - 3 = $\frac{x}{4}$ - $\frac{5}{4}$ ; y = $\frac{x}{4}$ - $\frac{5}{4}$ +3

y = $\frac{x}{4}$ - $\frac{17}{4}$ ; y = $\frac{x-17}{4}$ ; 4y = x - 17

7 0

2 years ago