Answer: The final molarity of a 20mL- 1.3M salt solution after it has been diluted with 100ml water is 0.22 M
Explanation:
According to the dilution law,
where,
= molarity of stock solution = 1.3 M
= volume of stock solution = 20 ml
= molarity of diluted solution = ?
= volume of diluted solution = (20+100) ml = 120 ml
Putting in the values we get:
Therefore the final molarity of a 20mL- 1.3M salt solution after it has been diluted with 100ml water is 0.22 M
It is a physical separation.
Only chemical separation involves the changing of substances and their bondings, which usually involves the use of heat or electricity. Meanwhile, physical changes does not require breaking the bonds of substances or changing a substance to another, common examples of physical separations are such as filtration or distillation.
Since straining pasta from water does not require breaking the pasta or water to other substances, plus heat and electricity is not involved, therefore this is a type of physical separation.
The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is : - 0.69°C
<h3>Determine the freezing point of the solution </h3>
First step : Calculate the molality of NaCl
molality = ( 2.5 grams / 58.44 g/mol ) / ( 230 * 10⁻³ kg/ml )
= 0.186 mol/kg
Next step : Calculate freezing point depression temperature
T = 2 * 0.186 * kf
where : kf = 1.86°c.kg/mole
Hence; T = 2 * 0.186 * 1.86 = 0.69°C
Freezing point of the solution
Freezing temperature of solvent - freezing point depression temperature
0°C - 0.69°C = - 0.69°C
Hence the Freezing temperature of the solution is - 0.69°C
Learn more about The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is : - 0.69°C
Answer:

Explanation:
From the question we are told that:
Mass of zinc 
Initial conc of HCl 
Initial volume of HCl
Molar mass of zinc
Generally the equation for reaction is mathematically given by

Generally the equation for moles of zinc
is mathematically given by



Generally the equation for moles of
is mathematically given by
Generally the reacted moles of HCl
is mathematically given by
Since
Zn:HCl =1:2
Therefore
![HCl_[reacted]=0.038*\frac{2}{1}](https://tex.z-dn.net/?f=HCl_%5Breacted%5D%3D0.038%2A%5Cfrac%7B2%7D%7B1%7D)
![HCl_[reacted]=0.076mol \ HCl](https://tex.z-dn.net/?f=HCl_%5Breacted%5D%3D0.076mol%20%5C%20HCl)
Generally the moles of HCl after Zn oxidization X is mathematically given by


Generally the conc of hydrochloride acid X is mathematically given by


Therefore Conc of HCl
