Help me asap pleaseeeeeeeeeeeeeeeeeee !!

A man buys a book for Rs 400 and sells it for Rs 420 his profit is

motikmotik

Answer:

20

Step-by-step explanation:

420-400=20

6 0

3 years ago

Read 2 more answers

Mrs. fam bought 4 1/4 pounds of ham for $17. At rate,What is the cost of 1 pound of sliced ham?

vova2212 [387]

$4 \frac{1}{4} \: Pounds = 17 \: USD \\ \frac{17}{4} \: Pounds = 17 \: USD \\ 1 \: Pound = 17 \times \frac{4}{17} = 4 \: USD$

!! Hope It Helps !!

3 0

3 years ago

Can you help me with 7 and 8

elena55 [62]

All I know or all I understood was both 7 and 8 aren’t functions. Hope this helped

4 0

3 years ago

. Ravi plays a game in which he has to draw one ball from a box containing 3 Red, 4 white and 3 green balls. On drawing a white

Slav-nsk [51]

P(Ravi is rewarded Rs. 10) = 0.4

P(Ravi does not lose) = 0.7

P(Ravi pays a penalty) = 0.3

Step-by-step explanation:

Step 1 :

Probability of any event happening = Total number of favorable outcomes / Total number of outcomes

Step 2 :

(i) P (Ravi is rewarded Rs. 10) = P(Ravi selecting a white ball)

Total number of favorable outcomes = Total number of white balls = 4

Total number number of outcomes = 10

Probability of selecting a white ball = Total number of white balls/Total number of outcomes =4/10 = 0.4

Hence P (Ravi is rewarded Rs. 10) = 0.4

Step 3 :

(ii) P (Ravi does not lose)

Probability of Ravi not losing is probability of Ravi not selecting a Red ball [ because Ravi has to pay penalty only when he chooses red ball

P(Ravi selecting Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi does not lose) = 1-0.3 = 0.7

Step 3 :

(iii)P (Ravi pays a penalty of Rs. 5)

P (Ravi pays a penalty of Rs. 5)= Ravi selecting a Red ball

P(Ravi selecting Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi pays a penalty of Rs. 5) = 0.3

5 0

3 years ago

The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08

kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So $\mu = 10*0.08 = 0.8$

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493$

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a $p = 0.4493$ probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.