The length of a rectangular room is 4 feet longer than twice the width. if the room's perimeter is 200 feet, what are the room's
dimensions?
2 answers:
P = 2(L + W)
P = 200
L = 2W + 4
200 = 2(2W + 4 + W)
200 = 2(3W + 4)
200 = 6W + 8
200 - 8 = 6W
192 = 6W
192/6 = W
32 = W <== the width is 32 ft
L = 2W + 4
L = 2(32) + 4
L = 64 + 4
L = 68 <=== the length is 68 ft
32 = w ----- the width is 32 feet
68 = L ------ the length is 68 feet
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