Question

The length of a rectangular room is 4 feet longer than twice the width. if the room's perimeter is 200 feet, what are the room's dimensions?

Answer 1

P = 2(L + W)
P = 200
L = 2W + 4

200 = 2(2W + 4 + W)
200 = 2(3W + 4)
200 = 6W + 8
200 - 8 = 6W
192 = 6W
192/6 = W
32 = W <== the width is 32 ft

L = 2W + 4
L = 2(32) + 4
L = 64 + 4
L = 68 <=== the length is 68 ft

Answer 2

32 = w ----- the width is 32 feet


68 = L ------ the length is 68 feet