B is the answer to your question
Just subtract 59/40 from 119/40
119/40-59/40=60/40
=6/4=3/2
So to make 59/40 equal to 119/40, we will add 3/2 to it
59/40+3/2=119/40
Answer:
B. 150 ft³
Step-by-step explanation:
The general formula for the volume of a pyramid is:
V =
where B = the area of the base and h = height of the pyramid
Since the base of the pyramid is a square, we can take the length of the side squared:
A = s²
A = 5² = 25 ft²
Using B = 25 and h = 18:
V = ![\frac{1}{3}*25*18=150ft^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%2A25%2A18%3D150ft%5E%7B3%7D)
Answer:
![V = 25d ^ 3 + 275d ^ 2 + 250d](https://tex.z-dn.net/?f=V%20%3D%2025d%20%5E%203%20%2B%20275d%20%5E%202%20%2B%20250d)
Step-by-step explanation:
If the pool has a rectangular shape then its volume can be written as:
V = Width * Length * Depth
Let's call:
w = width
l = length
d = depth.
So we know from the statement of the problem that:
![d = d](https://tex.z-dn.net/?f=d%20%3D%20d)
(5 feet more than 5 times the depth)
(50 feet more than 5 times the depth)
Then, the volume can be written according to the depth as:
![V = d(5 + 5d)(50 + 5d)](https://tex.z-dn.net/?f=V%20%3D%20d%285%20%2B%205d%29%2850%20%2B%205d%29)
![V = d[250 + 25d + 250d + 25d ^ 2]](https://tex.z-dn.net/?f=V%20%3D%20d%5B250%20%2B%2025d%20%2B%20250d%20%2B%2025d%20%5E%202%5D)
![V = 25d ^ 3 + 275d ^ 2 + 250d](https://tex.z-dn.net/?f=V%20%3D%2025d%20%5E%203%20%2B%20275d%20%5E%202%20%2B%20250d)
0.03b=j not sure if this is what you were looking for