Answer:
hiiii
Step-by-step explanation:
I'm here if anything!!! :)
Answer:
17 pages
Step-by-step explanation:
if not that then 15 since it says "less than 4,900 words in <u>15 pages</u>"
The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
Read more about rectangles at:
brainly.com/question/25292087
#SPJ1
Answer:
Length of rectangle = 16 cm
Width of rectangle = 4 cm
Step-by-step explanation:
Given:
Area of rectangle = 64 cm²
Find:
Length and width
Computation:
Assume;
Length of rectangle = a
So,
Width of rectangle = a -12
Area of rectangle = l x b
So,
a(a-12) = 64
a² - 12a - 64 = 0
a² - (16-4)a - 64 = 0
a² - 16a+ 4a - 64 = 0
a (a-16) + 4(a-16)= 0
(a-16)(a+4) = 0
a= 16 , a = -4
So,
Length of rectangle = 16 cm
Width of rectangle = a -12
Width of rectangle = 16 -12
Width of rectangle = 4 cm
Answer:
x=55
Step-by-step explanation:
The exterior angles of a polygon add to 360.
x+x+x+x+x+x+30 = 360
Combine like terms
6x+30 = 360
Subtract 30 from each side
6x+30-30 = 360-30
6x = 330
Divide by 6
6x/6 =330/6
x =55
