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IRINA_888 [86]
4 years ago
10

Simplify the expression (3+i)(2+i)

Mathematics
2 answers:
Ipatiy [6.2K]4 years ago
4 0

Answer:

5 +5i

Step-by-step explanation:

(3+i)(2+i)

FOIL

first 3*2 =6

outer: 3i

inner : 21

last i*i = i^2 = -1

Add them together

6+3i+2i-1

5 +5i

vovikov84 [41]4 years ago
3 0

Answer:

Step-by-step explanation:

hello :

(3+i)(2+i) = 6+3i+2i+i²      but : i² = -1

(3+i)(2+i) = 5+5i

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Jamie invests $1,200 in an account that earns 3% interest. Assuming continuous compounding, how much is in his account after 7 y
goblinko [34]

Answer:

The amount in account after 7 years of investment is $1478.4

Step-by-step explanation:

Given as :

The principal invested in account by Jamie = p = $1200

The rate of interest = r = 3% compounded annually

The Time period of investment = t=  7 years

Let The Amount in Jamie account = $ A

<u>For continuous compounding</u>

Amount = Principal × e^{r \times time}

Or, A = p × e^{r \times time}

Or, A = $1200 × e^{0.03 \times 7}

Or, A = $1200 × 2.71^{0.03 \times 7}

Or, A = $1200 × 1.232

∴  A = $1478.4

So, The amount after continuous compounding = A = $1478.4

Hence , The amount in account after 7 years of investment is $1478.4    Answer

5 0
4 years ago
4 terms of this sequence
weeeeeb [17]

Answer:

5,8,13,20

Step-by-step explanation:

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f(1)=1²+4=1+4=5

f(2)=2²+4=4+4=8

f(3)=3²+4=9+4=13

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3 0
3 years ago
Read 2 more answers
What is 9060000000 In standard form
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Complete this sentence. If volume remains the same while the mass of a substance ________, the density of the substance will____
Natasha_Volkova [10]
Since the
density =mass /volume
if volume is constant we can rewrite the density equation as
volume=mass / density
since volume is just a constant
c*density=mass
where c is some constant that denotes the constant volume
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4 0
3 years ago
The vertices of triangle PQR are given in the standard (x,y) coordinate plane below. What is the area, in the square coordinate
alekssr [168]

Answer:

Area = 12

Step-by-step explanation:

Given

See attachment

Required

Area of \triangle PQR

From the attached image, we have:

P = (6,10)

Q = (10,8)

R = (6,4)

The area is then calculated as:

A = \frac{1}{2}|(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y1 - x1y3)|

So, we have:

A = \frac{1}{2}|(6*8 - 10*10) + (10*4 - 6*8) + (6*10 - 6*4)|

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Remove absolute bracket

A = \frac{1}{2} * 24

A = 12

8 0
3 years ago
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