Answer:
c. narrower and translated down
Step-by-step explanation:
Answer:
-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.
Step-by-step explanation:
Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:
which tells us that the slope of the line is -2 and it y-intercept is "-3".
Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)
giving the x-coordinate 0 and the y-value where the line crosses the y-axis.
Complete question :
Wang Yong owes the bank $8500. To repay the debt, he paid a fixed amount back to the bank each month. After 12 months, his remaining debt was $6460. How much did Wang Yong pay each month?
Answer:
$170
Step-by-step explanation:
Given that:
Amount owed = $8500
Fixed amount replayed per month :
Amount left after 12 months = $6460
Amount paid per month :
Total amount paid over 12 months :
$(8500 - 6460) = $2040
Amount paid per month :
$2040 / 12
= $170
Step-by-step explanation:
I am not sure what your problem here is.
you understand the inequality signs ?
anyway, to get
6×f(-2) + 3×g(1)
we can calculate every part of the expression separately, and then combine all the results into one final result.
f(-2)
we look at the definition.
into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?
is -2 < -2 ? no.
is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.
so, we have to use
1/3 x³
for x = -2 that is
1/3 × (-2)³ = 1/3 × -8 = -8/3
g(1)
again, we look at the definition.
into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?
is 1 > 2 ? no.
is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.
so we have to use
2×|x - 1| + 3
for x = 1 we get
2×0 + 3 = 3
6×f(-2) = 6 × -8/3 = 2× -8 = -16
3×g(1) = 3× 3 = 9
and so in total we get
6×f(-2) + 3×g(1) = -16 + 9 = -7
