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3 years ago

Given the linear equation, 2x +4= 6, find the rate, initial value, and specific value.

Mathematics

1 answer:

kap26 [50]3 years ago

4 0

Answer: B. The rate is 2, the initial value is 4, and the specific value is 6.

Step-by-step explanation:

for a linear function y = a*x + b

Rate = coefficient that is multiplicating the variable. ( a in this case)

Initial value = value taken of y, when we have x = 0 (b in this case)

Specific value = value forced on y.

In this case, we have:

y = 6 = 2*x + 4

Then:

The coefficient multiplicating x is 2, so the rate is 2.

The constant term is 4, so the initial value is 4.

The value equal to y is 6, so the specific value is 6.

The correct option is B.

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Suppose that there were a positive correlation between the variables u and v. If v is 24 when u is 10, which of these is most li

sveta [45]

Answer:

The correct answer is 48, given by option c.

Step-by-step explanation:

This question can be solved by proportions, using a rule of three.

Positive correlation means that the variables are directly proportional, and thus, we apply cross multiplication.

If v is 24 when u is 10, which of these is most likely to be the value of v when u is 20?

24 - 10

x - 20

Applying cross multiplication:

$10x = 24*20$

Simplifying both sides by 10:

$x = 24*2 = 48$

The correct answer is 48, given by option c.

3 0

2 years ago

Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square

N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

Directrices at x = ±2
Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

$\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1$

So, we have:

$\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1$

Evaluate

$\frac{x^2}{10} + \frac{y^2}{15} = 1$

Hence, the equation of the hyperbola is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

Read more about hyperbola at:

brainly.com/question/3405939

#SPJ1

6 0

1 year ago

Which fraction is greater 4/6 or 5/100

Lina20 [59]

Answer:

4/6 is the greater of the two.

Step-by-step explanation:

4/6 = 200/300

5/100 = 15/300

200/300 is visibly clear to be larger than 15/300.

8 0

3 years ago

1462 divided by 58<br><br> To mixed number

GaryK [48]

Ur answer is 25/6/29 plz give brainliest

6 0

2 years ago

Hector is flying a kite. He has let out 86 feet

Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is $42.258333^{0}$ ≅ $42.26^{0}$

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = $\frac{opposite}{hypotenus}$

Sin $42.26^{0}$ = $\frac{x}{86}$

⇒ x = 86 x Sin $42.26^{0}$

= 86 x 0.6725

= 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

= 57.84 + 4

= 61.84 feet

7 0

2 years ago