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Greeley [361]
3 years ago
13

a ferry boat leaves the dock once per hour your waiting time for the next ferry will follow a uniform distribution from 0 to 60

minutes
Mathematics
1 answer:
olga55 [171]3 years ago
3 0
Ok but what is the question
You might be interested in
What is (x – 3)(2x + 1)
umka21 [38]

Answer:

(x – 3)(2x + 1)

Expand the terms

We get

2x² + x - 6x - 3

Final answer

2x² - 5x - 3

Hope this helps you.

3 0
3 years ago
The radius of a semicircle is 4 kilometers. What is the semicircle's diameter? I need this please
sergeinik [125]

Answer:

diameter = 8 km

Step-by-step explanation:

the diameter is equal to 2 times the radius

diameter = 2r

diameter = 2 • (4 km)

diameter = 8 km

7 0
2 years ago
The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
3 years ago
324 ft
kotegsom [21]

The distance between the flagpole and the building is the number of feet between them

The building is 162 feet from the flagpole

<h3>How to determine the distance</h3>

The given parameters are:

  • Flagpole = 40 feet
  • Building Shadow = 324 feet

The flagpole's shadow is 50% longer than the flagpole.

So, the length (l) of the flagpole's shadow is:

l = 40 * (1 + 50\%)

l = 60

The length of the building's shadow (d) is then calculated as:

60 : 40 =d :  324

Express as fraction

\frac{60}{40}= \frac{d}{324}

1.50 = \frac{d}{324}

Solve for d

d = 1.50 * 324

d = 486

The distance (x) of the building from the flagpole is then calculated as:

x = 486 - 324

x = 162

Hence, the building is 162 feet from the flagpole

Read more about distance and bearing at:

brainly.com/question/11744248

7 0
2 years ago
Need help ASAP!!! Thank you!!
Kay [80]
The example with the coin.
4 0
3 years ago
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