Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
Answer:
6.8818249813
Step-by-step explanation:
I didn't really get the problem but basically, according to "pemdas" you have to multiply 7x1910 and that would be 13370 and next you would do 92010 divided by 13370 which is 6.8818249813.
Answer:
1 no
2 I don't know
3 no
4 yes
5 2.5 is the slope
6 -0.5
7 no slope
Step-by-step explanation:
1 no because the y overlaps
2 not sure
3 it over laps
4 it never overlaps
5 y=2.5x-3
6 y=-0.5x+1
7 no slope it's just x=-2
for the 5-7 you can type that into demos and get more info
y=mx+b
m is the slope and b is y intercept
Answer:
B because the rotation of the wheel doesn't change the angle of the spokes.
Answer:
14x29=406 2hich would be the area
Step-by-step explanation:
