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andreev551 [17]
2 years ago
8

What is the 5th square number

Mathematics
1 answer:
Margaret [11]2 years ago
6 0
What do you mean?

here's some square numbers

<span>1, 4, 9, 16, 25, 36, 49…</span>
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Can somebody help, will give brainliest
grigory [225]

9514 1404 393

Answer:

  • c = 2
  • segments 10, 8, 6 (top down)

Step-by-step explanation:

The sum of top and bottom bases is twice the midsegment.

  (c² +6) +(c² +2) = 2(4c)

  2c² -8c +8 = 0 . . . . . . . . . subtract 8c

  2(c -2)² = 0 . . . . . . . . factor

  c = 2 . . . . . . the value that makes the binomial be zero

The value of c is 2; the segment lengths (top-down) are 10, 8, 6.

5 0
2 years ago
What does PIN stand for?
ankoles [38]

Answer:

Personal Identification Number

7 0
2 years ago
Read 2 more answers
Put in order from least to greatest 2.54, 5/2, 2.7, 15/7
MArishka [77]
15/7
5/2
2.54
2.7

That’s the order from least to greatest
3 0
3 years ago
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8fsquare + 4f - 60 <br> its an math equation can anyone plz gimme the answer
hammer [34]

Answer:

f = -3 , 5/2

Step-by-step explanation:

8f² + 4f - 60 = 0

Divide the entire equation by 4

2f² + f  - 15 = 0

Product = -30

Sum = 1

Factors = -5 , 6      {(-5)*6 = -30  and -5 +6 = 1}

2f² + f -15 = 0        {Rewrite the middle term using the factors}

2f² + 6f - 5f -15 = 0

2f(f + 3) - 5(f + 3) = 0

(f +3) (2f - 5) = 0

f +3  = 0    ; 2f -5 = 0

f = -3         ; 2f = 5

                    f = 5/2

6 0
2 years ago
If X is a random variable denoting number of defective items, which discrete probability distribution is appropriate
Lesechka [4]

Considering that for each item, there are only two possible outcomes, and the probability of an item being defective is independent of any other item, the binomial distribution is appropriate.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0
1 year ago
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